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ya B.H., e pe C.B.

METO B E EH H OPMATBHO ACT CEKTPA A M EHH X O EPOBCKX CHA OB C CO OBAHEM HE HE HO CCTEM BPEMEH B ca e np e e peee cnepa npepa a ee ccee pee ca, y p x y paca a c cene p. Ha c e cca e e n npe ee cnep cee nep cx aye x ca, annpcp a x n H a.

B oac epe paax coca- x xapaepc oceeo a cyaoo x copoce r (t), poox a ocoe pe- poecca.

opaoa yaeoo opaeoo o cce- p paoepo cpea uopaq yeoo oea cao, cyecye poea muoo oeau c ypoe aoa cyee papeae cocooc peax a pecae acco, coepa aoa poepyex oepocx opaoo- e ae caa, e epe pao ocoT = 1/ f f epex cce (C), paaa c po- e oe pee, e acoa eo pacoaa opaa epeoo c- cpea. yea apao aa. paa pacopa yaax poe oy, ao aoae, a papeacaa c ao coooe ypo oe- y cocooc papaaaeoo eoa ooo caa c oepoco acoo oea o ocooac ec coooe, ypo yo. pee [1]. pyo oe ca/ oee yooo cceoa paax y aoa ocaoo ocooac ooaeo poe eoxo oeu a- paee:

yex cuao c onepoco acmomo oUc / U.. 5,36 f / , (1) eau, coepae ay yaax coooe caa ya. Aa peax oe- e Uc U.. ee ae apepocx C paccapaeo oac epe- cooeceo oepocoo oea oaae, o aoee aeaa oe ya aoa.

caa e(t) oa oppoac a ocoe - Hapep, oecee ypo ya apae f oa eee 1% acoa cpea oa paec 19 pa oe acaoo e(t) = ec (t) + e (t), fc = 2 ae aco caa. p o paec (t) = {E /[r (t) t]}cos[ (t) t] e ca c ac- ep oyeoo acca eo paeaec a (t) oo oepa, E oe acaa;

a ax, a a pyx ocex ope (t) ca ya co cpeeapaec a- a copeex BM. Ta, p acoe ee. Haao aepee peax poec- fc = 210 , paepe ae ocea D = 1 a, co xapaepyec cooeceo coooe- epae ae cey paep acT = ca/y: (100...30)/1 1/(30..50). p ca P ye coca: P = T D fc 100 M. oo ceye ae, o p papaoe cope- peoc oc oceo p o ye paex oepocx C peae ca pe- ea epay [0,oc ] c paoep aoo opay, a pao, oceoaeoc (ac- pacpeee.

c) opo ae c paoepo cpe- Peauau oeu cuaa ya e (t), ae ao cec oea c oepoc- oo o cepa xapaepca eoy o acoo caa ya, pe oce yy, ooa oo c eoop oyeo co xapaepca ec o e . peaa oe caa ya ao yo, caoap poec paoe p ceocyae ca (CC), cya poecca.

oope cya caa o apaeaaa oppoa acca oceo pa- pa o x oac pee. O, cpoo eec a e cocae: oppoae c cce, c peyp, o oaa aao opeoc acca oceo pe- epoo, o oo pa o eoc peeo y opaoo oea aa oe caa. B oe cooa caa ya, c oppe yeo epooc- ceye coco oye CC:

2 2 4 $! ea opya oceoaeoc px peae 33 a. pcyce ax eoXn+1 = (a Xn + c) mod m, n 0, e oceoaeoc cy pao ea e oe, c ppaee, m oy, cyaoc C.

X0 aaoe aee; 5. Tec coa poepa (continuous test).

oceoaeoc ce oa c a- B o ece oceoaeoc ec a oaa Xn = (Xn-l + Xn-k ) mod m, n k l ; o 16 ce. p coae cooecy oceoaeoc ce a xoe o- x eo op yx oo ec e coo cooo pecpa c opa c. aec poe.

peoee, oopoe oao eepao- eaoe (aooe) oepocoe oeae oe peayec e yea a yaepa, oycoeo xopoe papaoaoc x cceyeoo oea o coa caa eop x ooceo pocoo. Ta peaa eo opyo oceoae- oye aa opa oe o oc {Xi} pecae coo cyay oce- peax oepocx C. ooy op eaoo oepocoo caa oppyc oaeoc oe, cooecyx ae o opye (2):

epae [0,2 ].

oe aeca eepa cyax ec (i) = cos[2 (2f0 r / c) i T /(N -1)], (2) ce (C) a opo peeo y f0 r e acoa caa oye; apoe (e) aeee aee ee eopeecoe cpoaoe aee copoc peaoo opeeee cacecx xapaepc oN oea; co opo; i oep op, o C o e pep. pai = 1,2,3,N. ocoy pecaee cao aoee a xapaepca ce ec po cpepoa, pc ooc epooce oppeoa e ec (i) [-1, 1], o eoo cooy. poepa cacecx xapaepc ec(i) a papo ce ca yoaec CC pooc a ocoe eco, peoea co max = 231 - 2 : ec (i) = ec (i) max, e oax caapo FIPS 140 aoaoo ec (i) [-max, max].

cya caapo CA:

a o yaao e, y poecc ca1. Tec oo (monobit test). Oeaoap, ceoaeo, aee eo cepec ae ex C. Tec caec c ocaec eac. ycao ypo poe, ec x ae cocae o 48% ya e (i) ooceo ypo caa ee o 52%.

acapy oe 1/ n1.

2. Tec oep. aoe co C paaB peax cceax c yeee paccoec a oeco 4-x ace, aa o o oea aya caa eec o opx coaco ee ae oocc oo ec (i) /(a i + b) a opaoy aoy:, e b eoecaa py. oce oo cec oeope oe. opeee ypo a x-apa coaco opye:

caa ooceo ypo ya oe ak (Ys - nps )2 aeoo epaa pee ( ) ee oi = N V =, e acaa n2, p oopo oec nps s=a N + b = n1 n2. B aa oe, oa i = 1, e V oea x-apa; Ys co ace, oea + b = n1 n oec:, oya ceye, o nps cex pye s ; oaeoe oeco aa = (n1 n2 -1) /(N -1), b = 1- a. Ceoaeo, ce pye s ; k co py. Tec caec poe (i) cyap eoppoa oppoae, ec epooc oo, o oea ye eH (i) ca yy opeec:

ee oyeo, ye ee paa 5%. ec (i) max e (i) n1 n2 -oo oo oc ycoe 7,V.

e (i) = +, a =, (3) 3. Tec eo (run test). pooc o- a i + (1- a) n1 N -c eoe pao op cox ec(i) (a i +1- a) + e (i) n0, 1. ae eo paec a e (i) =. (4) n1 + a i + (1- a) 6 py, ay oopx oaa eo oaoo . eo ee 5 a- oea opeoc oe ye cacac oey pyy. ae poo- ac ceyx o opeoce:

c oea x-apa. opeoc aoa;

4. Tec e eo (long runs). a- opeoc cpea;

ec poepe ae eoe, a oo- opeoc cex eoo.

$" 2 2.......

Oea x opeoce oaaa, o a- yae pecaa (cpao) a ocoe pyea opeoc oe eo opee- opa peyeo cee y acec, a opao, opeoc aoa o oepa.

peax A. pa o ae poecc aee eoxoo ae, o eoe oppoa epeoo caa peax cooae cpoex popaoe oeceoepocx C, opeoc oe oppe- ee (O) BM y peopaoa ype, o oea oo o cocae opa- o ce cpoo peopaoa ype oo caa oe poecca. p o pe- (), ooo oo cyax oye acaaec opeoc ocpoee aco ca opo ae caa e(t) c paoep = 2 / T T oepa oea o ee, o cpeae. B ao cyae p eT = tii - t acaa paoc ey o- e acoc (6) x cooae caoio a epexoa epe 0 tii tio cooeceo c eoo.

eaoo opoaoo cao, e ae- pee o poe peaaec, tii tio axoc poce eoa, a- y poe peopaoae ype o opa pep, eoo, ceyx. caa e(tH ), oppoa acc ae ceaa oe ooe e ocox apye- pao y caa e(tH ) a ocoe pe aapoac ope oepoc eoo [2] pae cepao y C cceye oea, aopaopx yc- poeoo cee caa eoc, ox poo cceoa o yee yoeopeo yco paoe ceepapeae cocooc peax poepy- o p:

ex oepocx C, coca oe eo[A x aeca, e pey oo opoocoS() = ()sin + B() cos ] + 2 x, apax o pee aypx ca.

(7) peaae emo eeu uopamu+ j[C()sin + D() cos ], 2 o acmu cnempa ayex onepocux cu- ao ca ooe aoap pecaeo C() e oe A(), B(),, D() opee oe. oee oo, ocoe ee aec opo caa. Ec poe co oe c eo cocao ac. Cy a eB (t ) pecae ooo peeo oH eoa aaec ceye. peapeB() C() pa, o opeee A(),,, D() e cceoa cepa caa, pecaeopeyc peya, peee [2], oooo (2), oo ycao, o cyecye pe c yeo ocaeo aa oo cceceya acoc ey aee eo ceapoa e a 1.

S( ) pao cocae c epao aMeoa ce acca cepa ay coo aoo eeca cepa eaeoo oepocoo oea eeo r :

ccee pee aaec ceye.

kT k Zp yc ca e(t) a epae, S( ) = k1 / 4 f0r / c = k1 / , (5) Zp ( oeco ex ooex ce) ae k1 oe acaa, ya cpoa opa ei.

aee T. (5) ceye, o, yea e y, oo ye ep opao Taa o oea a yo paax ycaoeo epao op (cee) caa e(t).

T eB (tH ) eB (t ) (t) H Ho ocoy y ec opap t < / p t < / B() apaepo, o oce yaao A() C() D() (p t > / ( t > / p e yee papeae cocooc eeB (tH ) = 0) eB (t ) = 0) H oa pa oepocx cao acoE E 0 0 o oac eoxoo epeecc eE E E t 0 eoe pe, acoc oopoo oe 4E 8 4E pecaea a E(1- ) t2 0 tH (t) = ( (t) t) /, (6) 8E 6 48 - E - - Et 0 33 e 0 oaeoe aee aco oepa (t) aae cee caa, oaea pe 2 2 4 $# man 1. aoo ae op ei man 5. Ha ocoe (9) oppyec paeopeeec aee eeoo pee e cepao ooc aapyeoo tHi (t) = ( (i t) i T ) / oppyec yxep- cee caa cxooo paea caa ptHj,p acc eeo, e j = mod4 (i) oca- o eea:

o o ee a 4 ca i, a o oaao S()= SB ()exp(- jtCM). (10) ae 2.

Bpaee (10) ooe opee cep p-o eea caa o eo pee opa man 2. oo, o ocooac eeo ccee pee. Ha x ocoe opaee cepo, pee [2], epeo oppoa acc ae cepao yxoa o y e(t ) poeo y H caa e(tH ), o ce opaoo , oppyc p ooepe acca tc, eB (tH ) cea aey, e - ycaoe = n, c eea cooeceo:

t a cpea cepa,,, n = 0,1,2, ,2m m Zp tc. p = (T3,p + T0,p ) / paepo k/4;

e - pa oe.

2m tk,p = (Ti,p - tc. p ) / paepo k;

man 6. Bcec acc ae oop = T3,p - T0, p paepo k/4.

oo cepa S (n) o o-cxee aopa, pecaeoo a pcye 1.

man 3. C e cooa apoca- oye a opao acc ae caa o epooo opye H- S (n) ooe ecoo pa cy a oa [3] (yeca epo) c pooeeco ayoo cepa oepocoo oo cpeae aoo p-o eea ea aapyeoo cee T , a ceopeec paeee paoc:

ce, cooec c (5) ecoo pa ye ay cep opaoo oee - e e1 - e0 e -e 2 3 11 = 12 = 13 = a oac aco 0.

,,, t1 - t0 t - t t3 - t2 Ha pcye 2 pecae cep ayeoo oepocoo oea c apaepa: co - 12 - 11 13 - 22 21 = = 31 = ooee ca/y aae oe poec,, t2 - t0 22 t3 - tt3 - t0, ca cooeceo: 30/1 1/30; f0 = 1 ; aee aao oeo copoc r cooe oe aS ceeoo ooa ceo 1000 /c 500 /c; co oceo :

eB (tH ) = a0 + a1t + a2t2 + a3tN=262144. a eeco cepa opaa3 = 31, a2 = 21 - 31(t0 + t1 + t2 ), a = 11 - 21(t0 + t1) + 31(t0t1 + t1t + t2t0 ), Taa 2.

. (8) 1 a0 = e0 - 11t0 + 21t0t1 + 31t0t1t2.

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